Question

Given x + y = x ∙ y = 3, determine x3 + y3 ?

Answer 1

Explanation:

x³ + y³ = (x + y)(x² - xy + y²)

= (x + y)(x² + 2xy + y² - 3xy)

= (x + y)[(x + y)² - 3xy]

= 3(3² - 3(3)) = 3(0) = 0