Question

Help, make sure to include units of measurement.​

Answer 1

`f=(9.0*{10}^(9)\frac{N.{m}^(2) }{ {c}^(2) })\frac{(3.2 *{10}^( - 9)c) \: (9.6 * {10}^( - 9)c) }{(0.32 m)^(2)} \\ \\ f=(9.0*{10}^(9)\frac{N.{m}^(2) }{ {c}^(2) })\ \frac{ \: 30.72 * {10}^( - 18) \: {c}^(2) }{ \: 0.1024 \: {m}^(2) } \\ \\f = \frac{9.0 * {10}^(9) * 30.72 * {10}^( - 18) }{0.1024} \: ( \frac{N.{m}^(2) }{ {c}^(2) } \: * \frac{ {c}^(2) }{ {m}^(2) } )\\ \\ f = \frac{276.48 * {10}^( - 9) }{0.1024} \: ( \frac{N.{m}^(2) }{ {c}^(2) } \: * \frac{ {c}^(2) }{ {m}^(2) } )\\ \\ f = 2700 * {10}^( - 9) N \\ \\ f = 2.7 * {10}^( - 6) N`

I hope I helped you^_^