Question

Please help me with this Pythagoras theorem..

A triangle DEF is right- angled at E, with DE=6.7m and EF=5.5m . find the length of DF. ​

Answer 1

8.7m

Explanation:

[6.7]²+5.5}²

=[75.14]

√75.14m

=8.7m

Answer 2

Explanation:

`{(df)}^(2) = {(de)}^(2) + {(ef)}^(2) \\ = {6.7}^(2) + {5.5}^(2) \\ = 44.89 + 30.25 \\ = 75.14 \\ df = √(75.14) = 8.67m \\ thank \: you`