Question

Solve the following ​

Answer 1

`x=2, \ y=1`

Explanation:

`\displaystyle \left \{ {{\text{Equation I:} \ \ 2x+y =5} \atop {\text{ Equation II:} \ \ 3x-2y=4}} \right.`

Multiply
`\text{Equation I}` by 2.

• 
  `2 \ \Big{[}2x+y=5\Big{]}`
• 
  `4x+2y=10`

Now we have this system of equations:

• 
  `\displaystyle \left \{ {{4x+2y =10} \atop {3x-2y=4}} \right.`

We can add the equations together to cancel out y.

• 
  `7x=14`
• 
  `x=2`

Substitute x = 2 into the first equation and solve for y.

• 
  `2(2)+y=5`
• 
  `4+y=5`
• 
  `y=1`

The solution to this system of equations is:

• 
  `x=2, \ y=1`
• or
  `(2, \ 1)`