Question

A Rocket is launched and reaches a height of 72m before falling back to Earth a) What was it's take off velocity? b) What was it's final velocity when it landed? c) What was it's velocity at the highest point?​

Answer 1

Answers are in the explanation

Step-by-step explanation:

a)

vf² = vi² + 2gh

0 = vi² + 2(-9.8)(72)

vi = 37.57 m/s

b)

vf = vi + gt

0 = 37.57 - (9.8)t

t = 3.83 s

3.83 x 2 = 7.67 s

vf = vi + gt

vf = 37.57 - (9.8)(7.67)

vf = -37.60 m/s

c)

Its vertical velocity at the highest point is 0 m/s