Question

How many atoms are in 6.3 mol Zn

Answer 1

3.8x1024atoms Zn

Step-by-step explanation:

is the answer

Answer 2

`\boxed {\boxed {\sf 3.8 * 10^(24) \ atoms \ Zn}}`

Step-by-step explanation:

We are asked to find how many atoms are in 6.3 moles of zinc (Zn). We will convert moles to atoms using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance.

In this problem, the particles are atoms of zinc. Therefore, there are 6.022 ×10²³ atoms of zinc in 1 mole of zinc.

We will convert using dimensional analysis, so set up a ratio using Avogadro's Number and the underlined information.

`\frac {6.022 * 10^(23) \ atoms \ Zn}{1 \ mol \ Zn}`

We are converting 6.3 moles of zinc, so we multiply the ratio by this value.

`6.3 \ mol \ Zn * \frac {6.022 * 10^(23) \ atoms \ Zn}{1 \ mol \ Zn}`

The units of moles of zinc cancel out.

`6.3 * \frac {6.022 * 10^(23) \ atoms \ Zn}{1 }`

A fraction with a denominator of 1 is equal to the numerator. We can disregard the denominator of 1.

`6.3 * 6.022 * 10^(23) \ atoms \ Zn`

`3.79386 * 10^(24) \ atoms \ Zn`

The original measurement of moles has 2 significant figures, so our answer must have the same. For the number we calculated that is the tenths place. The 9 in the hundredth place tells us to round the 7 in the tenths place up to an 8.

`3.8 * 10^(24) \ atoms \ Zn`

6.3 moles of zinc contains approximately 3.8 ×10²⁴ atoms of zinc.