Question

Helium has a density of 0.017 g/L. What is the volume of a weather balloon that contains 38 g of helium?

Answer 1

To find the volume of a weather balloon containing 38 g of helium, divide the mass of the helium by its density.

Step-by-step explanation:

To find the volume of a weather balloon containing 38 g of helium, we can use the density of helium, which is given as 0.017 g/L.

So, to find the volume (V) of the balloon, we can set up the following equation:

Density = Mass / Volume

0.017 g/L = 38 g / V

Cross multiplying, we get:

V = 38 g / 0.017 g/L = 2235 L

Therefore, the volume of the weather balloon containing 38 g of helium is 2235 L.

Answer 2

Answer: 2235 liters

Explanation: (38 grams)/(0.017 grams/L) = 2235 liters.

Note how the grams cancel and the liters moves to the top, to give a final result in just liters.

Note: this is a very large number. Under conditions of standard temperature and pressure (STP), 38 grams of helium would occupy just 212.8 liters (at STP, all gases occupy 22.4 liters per mole of that gas). But we are not given the environmental conditions here, other than it is a weather ballon. One would surmise that the balloon has risen far enough such that the pressure has becomve bery low.