Question

Jason is pulling a box across the room. He is pulling with a force of 27 newtons and his arm is making a 49 angle with the horizontal, what is the horizontal component of the force he is pulling with?

Answer 1

17.712 newtons

Explanation:

the horizontal component of the force = Fh

Fh = F. cos 49°

= 27. (0.656)

= 17.712 newtons

Answer 2

Force=27N

Angle=49

Vertical componenets:-

`\\ \sf\longmapsto Fsin\theta`

`\\ \sf\longmapsto 27sin49`

`\\ \sf\longmapsto 27(0.7)`

`\\ \sf\longmapsto 18.9N`