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Derivation of s= u+ 1/2 at2​

User Sarjit
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We know that

Velocity is given by the rate of change of position w.r.t time


\\ \sf\longmapsto v=(dx)/(dt)


\\ \sf\longmapsto vdt=dx

  • Now we can see in above v is not independent of t .So we replace the value of v by v=u+at and we get


\\ \sf\longmapsto (u+at)dt=dx

  • Integrate with limits 0 to t and x_o to x respectively .


\\ \sf\longmapsto u{\displaystyle{\int}_0^t}dt+a{\displaystyle{\int}_0^t}dt={\displaystyle{\int}^x_(x_0)}dx


\\ \sf\longmapsto ut+(1)/(2)at^2=(x-x_0)


\\ \sf\longmapsto x=x_0+ut+(1)/(2)at^2

User Yogesh Patil
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