Question

Write in standard form.
y^2+14y-5x+64=0

Answer 1

let's solve :

`\hookrightarrow \: {y}^(2) + 14y - 5x + 64 = 0`

`\hookrightarrow \: 5x = {y }^(2) + 14y + 64`

`\hookrightarrow \: 5x = {y}^(2) + 14y + 49 + 15`

`\hookrightarrow \: 5x = (y + 7) {}^(2) + 15`

`\hookrightarrow \: x = \frac{(y + 7) {}^(2) + 15 }{5}`

`\hookrightarrow \: x = (1)/(5) (y + 7) {}^(2) + 3`

therefore, the correct option is B

Answer 2

x = (1/5)(y + 7)² + 3

Step-by-step explanation:

Given that,

→ y² + 14y - 5x + 64 = 0

Let's find the required solution,

→ y² + 14y - 5x + 64 = 0

→ 5x = y² + 14y + 64

→ 5x = y² +14y +49 + 15

→ 5x = (y + 7)² + 15

→ x = [(y + 7)² + 15]/5

→ [x = (1/5)(y + 7)² + 3]

Hence, it is the correct answer.