Question

Graph a line that contains the point (-5,-3) and has a slope of −2

Answer 1

here u go :), good luck!

Answer 2

Heyo! ;D

So, considering this is talking about slope, it follows the rule of Δx over Δy, aka
`(rise)/(run)`.

This being said, the easiest way to solve this would be to first determine the location of the points. All you need to do is convert the given slope (-2) into a point. Bare in mind that 2 is the y (run) and 1 is the x (rise).

• 
  `-2 = -(2)/(1) = (1, -2) = (-1, 2)`

Next, use the given points from the question (-5, -3) with your new points, at them together separately, like this:

• 
  `(-5, -3) + (1, -2)`
• 
  `(-5 + 1, -3 + (-2))`
• 
  `(-5 + 1, -3 - 2)`
• 
  `(-4, -5)`

^This is adding (-5, -3) to (1, -2).

Hence, your first point will be (-4, -5).

Now, we add (-5, -3) to (-1, 2).

• 
  `(-5, -3) + (-1, 2)`
• 
  `(-5 + (-1), -3 + 2)`
• 
  `(-5 - 1, -3 + 2)`
• 
  `(-6, -1)`

Hence, your second point would be (-6, -1).

I attached a really helpful graph that can help you confirm your work. Otherwise, hope this helped you at the least move you closer to your answer! If this helped you, please lmk! Tysm, and good luck!