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A perpendicular is drawn from a point (-2,3) to the line 3y+2x=5. Find the equation of the perpendicular in the form y=mx+c.​

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Answer:

y = 3x/2 + 6

Explanation:

Find the equation of the line perpendicular to the line 2x + 3y = 5 passing through the point (−2,3).

The equation of the line in the slope-intercept form is y = 5/3 − 2x/3.

The slope of the perpendicular line is negative inverse: m = 3/2.

So, the equation of the perpendicular line is y = 3x/2 + a.

To find a, we use the fact that the line should pass through the given point:

3 = (3/2) ⋅ (−2) + a.

Thus, a = 6.

Therefore, the equation of the line is y = 3x/2 + 6.

Answer: y = 3x/2 + 6

User Cody S
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