Question

If sin(t) = 3/5 and t is in the 2nd quadrant, find cos(t).

Answer 1

Cosine is
`(hypotenuse)/(adjacent)`.

Apply the equation:

`sin(t) = (3)/(5) \\3^2 + b^2 = 5^2\\b^2 = 5^2 - 3^2\\\\√(b^2) = √(5^2)- √(3^2)\\\\\\b = 5 - 3 \\\\b = 2`

B is the adjacent side so

cosine is:

Cos(t) = 5/2

Have a great day,

And I hope this helps you!