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Find the distance between the two points rounding to the nearest tenth! PLEASE HELP ASAP!!!

Find the distance between the two points rounding to the nearest tenth! PLEASE HELP-example-1

2 Answers

6 votes

Answer:

10

Explanation:

d =√[(-3+9)²+(6+2)²]

= √(6²+8²)

=√(36+64)

=√100

= 10

User Beyondtheteal
by
5.7k points
3 votes

Answer:


\boxed {\boxed {\sf d=10}}

Explanation:

The distance between two points can be calculated using the following formula.


d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

In this formula, (x₁, y₁) and (x₂, y₂) are the two points. We are given the points (-9, -2) and (-3,6). If we match the value with the corresponding variable we see that:

  • x₁= -9
  • y₁= -2
  • x₂= -3
  • y₂= 6

Substitute the values into the formula.


d= \sqrt {(-3 - -9)^2 + (6 - -2)^2

Solve inside the parentheses. Remember that 2 back to back negative signs become a plus sign.

  • (-3 - -9)= (-3+9)= 6
  • ( 6- -2)= (6+2) =8


d= \sqrt{ (6)^2 + (8)^2

Solve the exponents. Multiply the number by itself.

  • (6)²= 6*6= 36
  • (8)²= 8*8= 64


d= \sqrt{(36)+(64)

Add.


d= \sqrt{100

Take the square root of the number.


d= 10

The distance between the points (-9, -2) and (-3, 6) is 10.

User AnasSafi
by
6.2k points