Question

Please someone help

Answer 1

`\begin{array}{l}\begin{cases} \begin{array}{l}\sin \alpha =(x)/(12) \Leftrightarrow x=12\sin \alpha \end{array}\\\cos \alpha =(y)/(12) \Leftrightarrow y=12\cos \alpha \end{cases}\\\\\text{Thus,\ the\ area\ is}\\\\A=(xy)/(2) =(12\sin \alpha \cdotp 12\cos \alpha )/(2)\\\\\Longrightarrow A=72\sin \alpha \cos \alpha \end{array}`

D