Question

A rocket blasts off and accelerates upward from rest with a rate of 15.4 m/s2. Calculate the

distance it will rise in 22 seconds.
NEED HELP!!

Answer 1

From question we have,

• Inital velocity(u) = 0
• Accleration(a) = 15.4 m/s²
• Time taken(t) = 22 sec

Now, from the second equation of motion;

• s = ut + ½at² { where s = distance covered }

Just put all the values provided in the question, in this equation;

• s = ut + ½at²
• s = (0 × 22) + ½ × 15.4 × 22 × 22
• s = 15.4 × 11 × 22
• s = 15.4 × 242
• s = 3726.8 m

Therefore, distance it will rise in 22 seconds will be 3726.8m