Answer:
Wagon weight 366.41314(9.81) = 3,594.5129 = 3590 N
Load weight 349.9245(9.81) = 3,432.75982 = 3430 N
Step-by-step explanation:
Let's assume the surface and the applied force are horizontal.
At constant motion, the friction force must balance the applied force
(from F = ma)
Ff = 77.3
μΝ = 77.3
μmg = 77.3
m = 77.3 / (0.011(9.81))
m = 716.3376... kg
Let M be the mass of the wagon
M + 0.955M = 716.3376
M(1.955) = 716.3376
M = 366.41314...kg
0.955 M = 349.9245... kg
round to the three significant digits of the question numerals.