Question

The P.E stored by a mass spring system at an extension of 2 cm is 10 J. The P.E stored by the same system at an

extension of 4 cm will be:

Answer 1

Step-by-step explanation:

extension(x) = 0.02m When the P.E is 10J.

extension(x)= 0.04m PE?.

P.E is proportional to Extension²

P.E/x² = P.E"/x"²

10/(0.02)² = P.E/(0.04)²

P.E= 10x(0.04)²/(0.02)²

P.E= 40J