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Given h(x) = 4x – 5, solve for a when h(x) = 7.

Given h(x) = 4x – 5, solve for a when h(x) = 7.
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Given h(x) = 4x – 5, solve for a when h(x) = 7.

User Madhav
by
8.2k points

2 Answers

1 vote

Answer:

23

Explanation:

h(7)= 4(7) - 5

h(7)= 28 - 5

h(7)= 23

User Jabba
by
8.0k points
3 votes

h(x)=4x-5


\\ \sf\longmapsto h(7)


\\ \sf\longmapsto 4(7)-5


\\ \sf\longmapsto 28-5


\\ \sf\longmapsto 23

User Lamon
by
7.9k points
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