212k views
1 vote
Find three consecutive even integers such that five times the second is six more than twice the sum

of the first and third integers

User Icyerasor
by
7.4k points

2 Answers

2 votes

Answer:

2x + 2x +2 + 2x +4 = 6x +6 =Sum

5 * (2x +2) = 2 * (2x + 2x +4) +6

10x + 10 = 8x + 8 + 6

2x = 4

x = 2

So the numbers are:

2x or 4

2 x + 2 = 6

2x + 4 = 8

Double-Check

5 * 2nd integer = 30

2 * (1st + 3rd integers) = 24

30 is 6 more than 24

Success!!!

Explanation:

User ArDumez
by
8.4k points
5 votes

Answer:

The first number = 4

The second number = 6

The third number = 8

Explanation:

Let all unknown numbers be represented by the variable x.

So;

x = first number

x + 2 = second number

x + 4 = third number

placing in a form as demanded by the question.

5(x + 2) = 6 + 2x + 2 ( x + 4)

5x + 10 = 6 + 2x + 2x +8

5x - 4x = 14 - 10

x = 4

Therefore;

The first number (x) = 4

The second number ( x + 2) = 4 + 2 = 6

The third number (x + 4) = 4 + 4 = 8

User Kyle Knoepfel
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories