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1 vote
Find f(4) for the function below.

f(x) = |x-7| + 3

User Yuncy
by
3.8k points

2 Answers

5 votes

Explanation:

f(x) = |x-7| + 3

when x is equal to 4, then

f(4) = |4-7| + 3

=-3+3

=0

User Raskolnikov
by
3.5k points
4 votes

Answer:


\boxed {\boxed {\sf f(4)= 6}}

Explanation:

We are asked to find f(4) for a function. We are finding the output or y-value when the input or x-value is 4.


f(x)= |x-7| +3

Substitute 4 for x in the function.


f(4) = |4-7| +3

Solve inside the absolute value signs.


f(4)= |-3|+3

The absolute value of a number is its distance from 0 on a number line. It is always the positive version of a number, so the absolute value of -3 is 3.


f(4)= 3+3

Add.


f(4)= 6

For the function f(x)= |x-7| +3, f(4) is equal to 6.

User Zmen Hu
by
3.3k points