446,782 views
14 votes
14 votes
Mother is three times as old as her daughter. Three years ago she was four times as old as her daughter was. Find their present ages.​

User Rogelio Monter
by
2.7k points

2 Answers

28 votes
28 votes

Answer:

daughter = 9yrs

mother = 27yrs

Explanation:

let age of daughter be x

age of mother = 3x

by qsn,

three yrs ago,

4 (x-3) = 3x-3

4x-12 = 3x-3

4x-3x = -3+12

× = 9 yrs (age of daughter )

3x = 3×9 = 27 yrs ( age of mother)

User SolveSoul
by
3.1k points
19 votes
19 votes
Let m represent the mother’s age and d represent the daughter’s age

m = 3d…(1)

(m-3) = 4(d-3), or
m - 3 = 4d - 12
m = 4d - 12 + 3
m = 4d - 9

m = 4d-9 …(2)

Substitute (1) into (2)

3d = 4d - 9
-d = -9
d = 9

Find the mother’s age by substituting d=9 into equation 1:
m=3d
m=3(9)
m=27

Therefore, the mother is 27 years and the daughter is 9 years old now
User Mengmeng
by
2.8k points