Answer:
Part A)
Approximately 318.1318 meters.
Part B)
Approximately 137.7551 meters.
Explanation:
The path of a projectile is given by the equation:

Part A)
The range of the projectile will be given by the difference between its starting point and landing point. In other words, its two zeros.
Let y = 0 and solve for x:

Factor:

Zero Product Property:

Solve for each case:

Hence, the range of the projectile is approximately (318.1318 - 0) or 318.1318 meters.
Part B)
Since the equation is a quadratic, the maximum height is given by its vertex. Recall that the vertex of a quadratic is given by:

In this case, a = -49/9000 and b = √3.
Find the x-coordinate of the vertex:

Then the maximum height will be:

The maximum height reached by the projectile will be 137.7551 meters.