Question

Help for 15 points . ill up it

Answer 1

Explanation:

Let
`P_1(-1, -8)\:\text{and}\:P_2(-4, -9)`

The slope of the line through these two points is

`m = (y_2 - y_1)/(x_2 - x_1) = ((-9 + 8))/((-4 + 1)) = (1)/(3)`

So the slope-intercept form of the line passing through the two points is

`y = mx + b = (1)/(3)x + b`

To find b, we use either point into our equation. Let's use (-1, -8):

`-8 = (1)/(3)(-1) + b \Rightarrow b = -(23)/(3)`

Therefore, the slope-intercept form of the equation for the line is

`y = (1)/(3)x - (23)/(3)`

The standard form of the equation can be written as

`x + 3y + 23 = 0`