Question

Calculate the mass of 5.00x10^25 atoms of AgNO3

Answer 1

1.41 x 10 ^4

Step-by-step explanation:

change atoms to mol then to gram

5 x 10^25 atoms of AgNO3
`(1mol AgNO3)/(6.023 x 10 ^23)`
`(169.91g)/(1mol AgNO3)`

= 141.05g x 10^2 move the decimal over if you are doing sig fig 1.41 x 10^4

change atoms to mol using Avogadro's number 6.023 x 10^23 then mol to gram using the molar mass of AgNO3.