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01:15:51 Differential equation of the family of circles touching the y-axis at origin is


User Mtk
by
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1 Answer

6 votes

Explanation:

Correct option is

B

x

2

−y

2

+2xy

dx

dy

=0

The system of circles touching Y axis at origin will have centres on X axis. Let (a,0) be the centre of a circle. Then the radius of the circle should be a units, since the circle should touch Y axis at origin.

Equation of a circle with centre at (a,0) and radius a

(x─a)²+(y─0)²=a²

That is,

x²+y²─2ax=0 ─────► (1)

The above equation represents the family of circles touching Y axis at origin. Here 'a' is an arbitrary constant.

In order to find the differential equation of system of circles touching Y axis at origin, eliminate the the arbitrary constant from equation(1)

Differentiating equation(1) with respect to x,

2x+2ydy/dx─2a=0

or

2a=2(x+ydy/dx)

Replacing '2a' of equation(1) with the above expression, you get

x²+y²─2(x+ydy/dx)(x)=0

That is,

─x²+y²─2xydy/dx=0

or

x²─y²+2xydy/dx=0

User Andrew Hardiman
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