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5 votes
Simplify the power of i.
i78
A -1
B -i
C 1
D i

1 Answer

3 votes


\\ \rm\longmapsto i^(78)

  • Divide 78 by 4


\\ \rm\longmapsto (78)/(4)


\\ \rm\longmapsto (39)/(2)


\\ \rm\longmapsto 19(1)/(2)

Now

remainder is 2


\\ \rm\longmapsto i^2


\\ \rm\longmapsto (√(-1))^2


\\ \rm\longmapsto -1

Hence


\\ \rm\longmapsto i^(78)=-1

User DonP
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