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Which is the equation of the line that passes through (6, 2) and is perpendicular to a line with slope -1/3? ​

Which is the equation of the line that passes through (6, 2) and is perpendicular-example-1

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5 votes

Answer:

(c) y = 3x - 16 or y - 2 = 3(x - 6)

Explanation:

To be perpendicular, the slope must be the negative inverse of the other line,

so we know the slope must be -(-3/1) = 3

then the general point-slope form is

y = mx + b (m = slope and b = y-intercept) so

y = 3x + b (then use the point given (6,2) to find m)

2 = 3(6) + b

2 = 18 + b

2 - 18 = b

-16 = b

then

y = mx + b

y = 3x - 16

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