Question

Help I don’t understand at all

Answer 1

`1)\ \ 4h^2-13h+6\\2)\ \ 7x^3y^2-x^2y+1\\3)\ \ -7n+2\\4)\ \ -8m+4`

Explanation:

1.

Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.

`2h^2-7h+2h^2-h+6+4h-9h`

`(2h^2+2h^2)+(-7h-h+4h-9h)+(6)`

`4h^2-13h+6`

2.

Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.

`8x^3y^2-7x^2y+8x-4-x^3y^2+2x^2y+4x^2y-8x+5`

`(8x^3y^2-x^3y^2)+(-7x^2y+2x^2y+4x^2y)+(8x-8x)+(-4+5)`

`7x^3y^2-x^2y+1`

3.

Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following (
`a(b+c)=(a)(b)+(a)(c)=ab+ac`). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,

`-2(8n+1)-(5-9n)+3^2`

`-2(8n+1)-(5-9n)+(3*3)`

`-2(8n+1)-(5-9n)+9`

`(-2)(8n)+(-2)(1)+(-)(5)+(-)(-9n)+9`

`-16n-2-5+9n+9`

`(-16n+9n)+(-2-5+9)`

`-7n+2`

4.

The same method used to solve problem (3) can be applied to this problem.

`(1)/(2)(10-8m+6m^2)-(3m^2+4m-7)-2^3`

`(1)/(2)(10-8m+6m^2)-(3m^2+4m-7)-(2)(2)(2)`

`((1)/(2))(10)+((1)/(2))(-8m)+((1)/(2))(6m^2})+(-)(3m^2)+(-1)(4m)+(-1)(-7)-8`

`5-4m+3m^2-3m^2-4m+7-8`

`(-3m^2-3m^2)+(-4m-4m)+(5+7-8)`

`-8m+4`