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The perimeter of a playing field for a certain sport is 178 ft. The field is a rectangle, and the length is 43 ft longer than the width. Find the dimensions

The width of the playing field is
(Type an integer or a decimal.)

1 Answer

2 votes

Answer:

23 and 66 are the dimensions

Explanation:

178/2=89

89+43=132

178-132=46

132/2=66

46/2=23

(I think this is the answer I'm so sorry if I am wrong)

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