Question

The sum of three numbers is 124. The second is 10 less than the first. The third number is 4 times the second. What are the numbers?

Answer 1

Explanation:

numbers

first = X

second = (x-10)

Third = 4(x-10)

x + (x-10) + 4(x-10) = 124

2x -10 + 4x-40 =124

6x - 50 = 124

6x = 124 + 50

6x = 174

x= 29

therefore the ;

first number = 29

second = (x-10) = 29-10 = 19

third= 4(x-10) = 4(29-10)= 76