Question

A regular polygon has exterior angles of 60°

What is the sum of the polygon’s interior angles?

Answer 1

The sum of the exterior angles of a regular polygon is 360º

Each exterior angle of a regular polygon is 60º/n

360º/n=60º

360/60=n

6=n

A polygon with 6 sides is a hexagon.

Use the formula (n-2)×180

(6-2)*180=4*180=720º

another solution...

you have 6 interior angles (hexagon)

if an exterior angle is 60º, the corresponding interior angle is 180-60=120º

you have 6 of these 120º angles

6*120=720º

Answer 2

720°

Explanation:

The sum of the exterior angles of a polygon = 360°

Divide by 60 to find number of sides (n)

n = 360° ÷ 60° = 6

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

Here n = 6 , then

sum = 180° × 4 = 720°