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If y - 1/y =8 then find the value of y^2-1/y^3​
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If y - 1/y =8 then find the value of y^2-1/y^3​

User JoLoCo
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Explanation:


{y}^(2) - \frac{1}{ {y}^(3) }

factorise out y² ;


= {y}^(2) (1 - (1)/(y) ) \\ \\ = 8 {y}^(2)

User MStoner
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