Question

Answer this question​

Answer 1

`\huge\boxed{width=12cm}`

Explanation:

`l-length\\w-width\\P-perimeter`

The formula of perimeter of the rectangle:

`P=2l+2w=2(l+w)`

Substitute:

`l=6w\\\\P=168cm`

`168=2(6w+w)\\168=2(7w)\\168=14w\qquad|\text{divide both sides by 14}\\\\(168)/(14)=(14w)/(14)\\\\12=w\Rightarrow w=12(cm)`

Answer 2

Width of rectangle = 12 cm

Explanation:

Let us assume that,

→ Length = 6x

→ Width = x

→ Perimeter = 168 cm

Perimeter of rectangle,

→ P = 2(L + W)

Forming the equation,

→ 168 = 2(6x + x)

Now the value of x will be,

→ 168 = 2(6x + x)

→ 2 × 7x = 168

→ 14x = 168

→ x = 168/14

→ [ x = 12 ]

Then the length and width is,

→ Length = 6x = 6(12) = 72 cm

→ Width = x = 12 cm

Hence, required width is 12 cm.