Question

The hypotenuse of a right triangle measures nem and one of its legs measures o em.

Mnd the measure of the other leg. If necessary, round to the nearest tenth.
Sun
attempt to

Answer 1

• H=11cm
• B=9cm
• P=?

Using Pythagorean theorem

`\\ \sf\longmapsto P^2=H^2-B^2`

`\\ \sf\longmapsto P^2=11^2-9^2`

`\\ \sf\longmapsto P^2=121-81`

`\\ \sf\longmapsto P^2=40`

`\\ \sf\longmapsto P=√(40)`

`\\ \sf\longmapsto P=6.2cm`

Answer 2

Explanation:

Given,

Hypotenuse = 11 cm

Base (One of the given leg) = 9 cm

Therefore,

According to Pythagoras Theorem,

`{base}^(2) + {height}^(2) = {hypotenuse}^(2)`

`= > {(9)}^(2) + {height}^(2) = {(11)}^(2)`

`= > {height}^(2) = {(11)}^(2) - {(9)}^(2)`

`= > {height}^(2) = 121 - 81`

`= > {height}^(2) = 4 0`

`= > height = √(40)`

=> height = 6.3245553203

When rounded to nearest tenth,

=> height = 6.3

Hence,

Required length of other leg is 6.3 (Ans)