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the sum of two resistors in 750 ohms. One is 6.5 times the other. Find the size of each resistor in ohms.

2 Answers

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Answer:

r = 100

6.5r = 650

Explanation:

let r be resistors.

6.5r + r = 750

Simplify:

6.5r + r = 750

7.5r = 750

------ ------

7.5 7.5

r = 100

100 × 6.5 = 650

One resistor is 100 ohms, and he other is 650 ohms.

Hope this helped.

User TheBlueSky
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5.4k points
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G I V E N :

The sum of two resistors in 750 ohms. One is 6.5 times the other. Find the size of each resistor in ohms.

S O L U T I O N :

According to the question, here we need to take a variable to find the size of each resistor then multiply 6.5 with the variable with the first one. For the second there is no change in the variable. Then adding them we get 750 ohms. Simplifying we get their respective size

Let us assume the other resistor's size be x

Here,

The First resistor's size is 6.5 times the other. Hence, the no. is 6.5x

Given that : the sum of two resistors in 750 ohms

  • 1st Resistor + 2nd Resistor = 750 ohms

  • 6.5x + x = 750 ohms

  • 7.5x = 750 ohms

  • x = 750/7.5 ohms

  • x = 100 ohms

FINDING SIZE :

First Resistor's Size = 6.5x = 6.5*100 = 650 ohms

Other Resistor's Size = x = 100 ohms

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[Note : Symbol of ohm is Ω]

User Apangin
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