Question

1. Find the HCF of the following numbers by prime factorisation and continued division method10,35,40​

Answer 1

Explanation:

10 = 2*5

35 = 5*7

40 = 2*2*2*5

The number 5 is common to all three factorisations

So the HCF = 5.

Continued division:

10 and 35:

10) 35(3

30

5)10(2

10

0

- so the HCF of 10 and 35 is 5.

10 and 40:

10)40( 4

40

0

So the HCF of 10 and 40 is 10

We found HCF of 10 and 35 is 5 so:

HCF of 10, 35 and 40 is HCF of 5 and 10 which is 5.