Answer:
Let the plane be flying east (to the right) and the wind north
Vx = 650 km/hr i speed to East
Vy = 75 km/hr j speed to North
V = (650^2 + 75^2)^1/2 = 654 km/hr net speed
tan θ = Vy / Vx = 75 / 650 = .115 θ = 6.58 deg N of E
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