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Differentiate y=2x+200/x with respect to x

User EddieBytes
by
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2 Answers

7 votes

Answer:


(dy)/(dx ) = 2 - \frac{200}{ {x}^(2) }

Explanation:


the \: equation \: can \: be \: rewriten \: as \\ y = 2x + 200 {x}^( - 1) \\ \\ now \: differentiate \: the \: equation\ \\ (dy)/(dx) = 2 - 200 {x}^( - 2) \\ (dy)/(dx) = 2 - \frac{200}{ {x}^(2) }

User Timidger
by
8.5k points
0 votes

Answer:

Hello,


\boxed{y'=2-(200)/(x^2) }\\

Explanation:


(f(x)+g(x))'=f'(x)+g'(x)\\\\(2x)'=2*(x)'=2*1=2\\\\((200)/(x) )'=200*(x^(-1))'=200*(-1)*x^(-1-1))=-(200)/(x^2) \\\\\\\boxed{y'=2-(200)/(x^2) }\\

User Lsdr
by
8.9k points

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