Question

How would the expression x^2 -9 be rewritten using Difference of Squares?

O A. (x+3)(x - 3)
O B. (X-9)^2
O C. (x +9)(x-9)
O D. (x+3)^2

Answer 1

`\left(x+3\right)\left(x-3\right)`

Explanation:

`x^2 -9`

To factor an integer, we need to divide it by the ascending sequence of primes (2, 3, 5). The number of times each prime divides the original integer becomes its exponent.
`3^(2) =9`

Now, we need to factor this expression by applying the difference of two squares rule:

`A^(2) -B^(2) =(A+B)(A-B)`

A= x and B= 3

`(x+3)(x-3)`

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Answer 2

A. (x+3)(x - 3)

Explanation:

x^2 -9

Rewriting

x^2 - 3^2

We know that a^2 - b^2 = (a-b)(a+b)

(x-3)(x+3)