Question

A train moving west with an initial velocity of 20 m/s accelerates at 4 m/s2 for 10 seconds. During this tim

moves a distance of
meters.

Answer 1

400m

Step-by-step explanation:

`x = v_(0)t + (at^(2) )/(2) \\x = 20*10+(4*10x^(2) )/(2) = 400m`