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A mirror forms an erect image 40cm from the object and one third its height where must the mirror be situated ​
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A mirror forms an erect image 40cm from the object and one third its height where must the mirror be situated ​

User Zacqary
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1 Answer

4 votes
  • image distance=-40cm=v
  • Object distance=u=?
  • Magnification=m=3

We know


\boxed{\sf m=-(v)/(u)}


\\ \sf\longmapsto 3=-(-40)/(u)


\\ \sf\longmapsto 3=(40)/(u)


\\ \sf\longmapsto u=(40)/(3)


\\ \sf\longmapsto u=13.3cm

User Zeroef
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