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4 votes
Integrate[Exp[Power[sinx,2]]sin2x,x]

User Huha
by
7.3k points

1 Answer

1 vote

Answer:

e^{sin²x}+c

Explanation:


\int e^(sin^2x) sin 2x dx=?

is this statement?

if so

then


put~sin^2x=t\\differentiate\\2 sin ~x~cos~x~dx=dt\\sin~2x ~dx=dt\\\int e^t~dt=e^t+c\\=e^(sin^2x)+c

User Helen Wood
by
6.5k points