Question

Using these metal ion/metal standard reduction potentials calculate cell potential for Cu2+(aq) + Cd(s) →Cd2+(aq)+ Cu(s) Cu2+(aq)|Cu(s) + 0.34 VNi2+(aq)|Ni(s) -0.25 Cd2+(aq)/Cd(s) -0.4V

Answer 1

Cd(s) ---------------------->
`Cd^(+2)` (aq) + 2
`e^-` ,
`E_0` = 0.34 v

`Cu^(+2)` (aq) + 2
`e^-` ------------> Cu (s) ,
`E_0` = -0.04 v

----------------------------------------------------------------------------------------------

Cd(s) +
`Cu^(+2)` (aq) ------------->
`Cd^(+2)` (aq) + Cu (s) ,
`E_0` = 0.30 v

The cell potential is defined as the measure of
`\text{ potential difference }` between the
`\text{two half cells}` of an electrochemical cell.