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PLEASE HELP! 100 POINTS! Spam = Report! See the attached image for the problem.

This problem is related to scatterplots.

PLEASE HELP! 100 POINTS! Spam = Report! See the attached image for the problem. This-example-1
User Aleksandrus
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1 Answer

22 votes
22 votes

Answer:

69 °F

Explanation:

The regression line of
y on
x is:
y = a + bx

(where
a is the y-intercept and
b is the slope)

From inspection of the graph:


\textsf{slope}\:(b)=\frac{\textsf{change\:in}\:y}{\textsf{change\:in}\:x}=\frac13

Using point (66, 58) and the found value of b to find the equation of the regression line:


\implies y-58=\frac13(x-66)


\implies y=36+\frac13x

To find the likely outside temperature if the crickets were measured to chirp 99 times in one minute, simply substitute
x=99 into the equation:


\implies 36+\frac13(99)=69

Important:

When we use values of x outside the range of the original data to predict corresponding values of y, it is call "extrapolation". These predictions can be unreliable because there is no evidence that the relationship described by the regression line is true for all values of x.

User Lawls
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2.8k points