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8 votes
How many real solutions does the equation 8x2 - 10x + 15 = 0 have?

User Radiorz
by
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2 Answers

16 votes
16 votes

Answer:

2

Explanation:

8x^2 - 10x + 15 = 0 = formula -b +/- sqrt b^2 -4 * a * c / 2a = (- -10 ) = input +10+ (sqrt 10^2 -4 *( 8 * 15) ) /( 2* 8) = 10 +sqrt (96 * 120) / 16 = 10+ sqrt 11520 /16 = 16.7082039 and 10- (sqrt 10^2 -4 *( 8 * 15) ) /( 2* 8) = 10 -sqrt (96 * 120) / 16 = 3.29179607

User Ori Dar
by
3.4k points
10 votes
10 votes


8 {x}^(2) - 10x + 15 = 0

we have: delta = b² - 4ac = (-10)² - 4.8.10 = - 380 < 0

So: no solution.

Ok done. Thank to me :>

User Marcel Wasilewski
by
3.1k points