Question

Given OSALE, solve for x.
3
3x + 4
5x-6
S
3
A

Answer 1

Two parallel sides is 3x + 4 = 5x - 6

`\bf \large \longrightarrow \: \: 3x \: + \: 4 \: = \: 5 x \: - \: 6`

`\bf \large \longrightarrow \: \:6 \: + \: 4 \: = \: 5x \: - \: 3x`

`\bf \large \longrightarrow \: \:10 \: = \: 2x`

`\bf \large \longrightarrow \: \: (10)/(2) \: = \: x \\`

`\bf \large \longrightarrow \: \: \cancel(10)/(2) \: \large \: ^(5) \: = \: x \\`

`\bf \large \longrightarrow \: \:x \: = \: 5`

Option ( B ) is the correct answer.

Answer 2

x=5

Explanation:

The sides have to be equal length

3x+4 = 5x-6

Subtract 3x from each side

3x+4-3x = 5x-6-3x

4 = 2x-6

Add 6 to each side

4+6 = 2x-6+6

10 = 2x

Divide by 2

10/2 =2x/2

5 =x