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4 votes
Find the quadratic equations whose roots are 3 and -4


2 Answers

0 votes

Answer:

Explanation:


\displyastyle \Large \boldsymbol{} (x-x_1)(x-x_2) \ \ x_1 \ ; \ x_2 -roots \\\\(x-3)(x-(-4))=(x-3)(x+4)=\boxed{x^2+x-12}

User Rzlvmp
by
6.0k points
5 votes

Answer:

Hello,

Explanation:

(x-3)*(x+4)=0 or x²+x-12=0

User Antho Christen
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6.4k points