Question

Find the Area of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenth place.

6 9

Answer 1

For rectangle

Area:-

• Length ×Breadth
• 9(6)
• 54units^2

For semicircle

• Radius=6/2=3

Area:

• πr^2/2
• 9π/2
• 4.5π
• 14.13units^2

Total:-

• 54+14.13
• 68.13units^2

Answer 2

Answer: 68.1

Explanation:

The area of a semi-circle is 1/2 the area of a full circle. The area of a full circle is pi*r^2. Therefore, the area of a semi-circle is:

`Area=\pi r^2/2`

`Area=\pi (3)^2/2=9\pi /2`

The area of a rectangle is the length multiplied by the width:

`Area=l*w`

`Area=6*9=54`

The net area is the sum of the rectangle and the semi-circle:

`Area=(9\pi /2)+(54)=68.1`