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Answer:
(x -2)^2/16 +(y +2)^2/4 = 1
Explanation:
The equation of an ellipse is ...
((x -h)/a)^2 +((y -k)/b)^2 = 1
where (h, k) is the center, and 'a' and 'b' are the semi-axes in the x- and y-directions respectively.
Here, we have (h, k) = (2, -2), and a=6-2 = 4, b = 0-(-2) = 2. Then the equation is ...
((x -2)/4)^2 +((y +2)/2)^2 = 1
More conventionally, the denominators are multiplied out, so this is ...
(x -2)^2/16 +(y +2)^2/4 = 1